174 lines
4.8 KiB
Swift
174 lines
4.8 KiB
Swift
/**
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* File: binary_search_tree.swift
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* Created Time: 2023-01-26
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* Author: nuomi1 (nuomi1@qq.com)
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*/
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import utils
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/* Binary search tree */
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class BinarySearchTree {
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private var root: TreeNode?
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/* Constructor */
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init() {
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// Initialize empty tree
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root = nil
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}
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/* Get binary tree root node */
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func getRoot() -> TreeNode? {
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root
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}
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/* Search node */
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func search(num: Int) -> TreeNode? {
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var cur = root
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// Loop find, break after passing leaf nodes
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while cur != nil {
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// Target node is in cur's right subtree
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if cur!.val < num {
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cur = cur?.right
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}
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// Target node is in cur's left subtree
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else if cur!.val > num {
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cur = cur?.left
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}
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// Found target node, break loop
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else {
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break
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}
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}
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// Return target node
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return cur
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}
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/* Insert node */
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func insert(num: Int) {
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// If tree is empty, initialize root node
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if root == nil {
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root = TreeNode(x: num)
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return
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}
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var cur = root
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var pre: TreeNode?
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// Loop find, break after passing leaf nodes
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while cur != nil {
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// Found duplicate node, thus return
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if cur!.val == num {
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return
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}
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pre = cur
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// Insertion position is in cur's right subtree
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if cur!.val < num {
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cur = cur?.right
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}
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// Insertion position is in cur's left subtree
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else {
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cur = cur?.left
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}
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}
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// Insert node
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let node = TreeNode(x: num)
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if pre!.val < num {
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pre?.right = node
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} else {
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pre?.left = node
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}
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}
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/* Remove node */
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func remove(num: Int) {
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// If tree is empty, return
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if root == nil {
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return
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}
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var cur = root
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var pre: TreeNode?
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// Loop find, break after passing leaf nodes
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while cur != nil {
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// Found node to be removed, break loop
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if cur!.val == num {
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break
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}
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pre = cur
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// Node to be removed is in cur's right subtree
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if cur!.val < num {
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cur = cur?.right
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}
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// Node to be removed is in cur's left subtree
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else {
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cur = cur?.left
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}
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}
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// If no node to be removed, return
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if cur == nil {
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return
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}
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// Number of child nodes = 0 or 1
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if cur?.left == nil || cur?.right == nil {
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// When the number of child nodes = 0/1, child = null/that child node
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let child = cur?.left ?? cur?.right
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// Remove node cur
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if cur !== root {
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if pre?.left === cur {
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pre?.left = child
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} else {
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pre?.right = child
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}
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} else {
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// If the removed node is the root, reassign the root
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root = child
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}
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}
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// Number of child nodes = 2
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else {
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// Get the next node in in-order traversal of cur
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var tmp = cur?.right
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while tmp?.left != nil {
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tmp = tmp?.left
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}
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// Recursively remove node tmp
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remove(num: tmp!.val)
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// Replace cur with tmp
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cur?.val = tmp!.val
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}
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}
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}
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@main
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enum _BinarySearchTree {
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/* Driver Code */
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static func main() {
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/* Initialize binary search tree */
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let bst = BinarySearchTree()
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// Note that different insertion orders can result in various tree structures. This particular sequence creates a perfect binary tree
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let nums = [8, 4, 12, 2, 6, 10, 14, 1, 3, 5, 7, 9, 11, 13, 15]
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for num in nums {
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bst.insert(num: num)
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}
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print("\nInitialized binary tree is\n")
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PrintUtil.printTree(root: bst.getRoot())
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/* Search node */
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let node = bst.search(num: 7)
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print("\nFound node object = \(node!), node value = \(node!.val)")
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/* Insert node */
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bst.insert(num: 16)
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print("\nAfter inserting node 16, the binary tree is\n")
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PrintUtil.printTree(root: bst.getRoot())
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/* Remove node */
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bst.remove(num: 1)
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print("\nAfter removing node 1, the binary tree is\n")
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PrintUtil.printTree(root: bst.getRoot())
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bst.remove(num: 2)
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print("\nAfter removing node 2, the binary tree is\n")
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PrintUtil.printTree(root: bst.getRoot())
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bst.remove(num: 4)
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print("\nAfter removing node 4, the binary tree is\n")
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PrintUtil.printTree(root: bst.getRoot())
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}
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}
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